(w-3)^2=29-5w

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Solution for (w-3)^2=29-5w equation: 



(w-3)^2=29-5w

We move all terms to the left:

(w-3)^2-(29-5w)=0

We add all the numbers together, and all the variables

(w-3)^2-(-5w+29)=0

We get rid of parentheses

(w-3)^2+5w-29=0

We add all the numbers together, and all the variables

5w+(w-3)^2-29=0

We move all terms containing w to the left, all other terms to the right

5w+(w-3)^2=29

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